Challenge Prelims V1.0 – Day 11 – CSAT Paper

1. How many natural numbers are there which give a remainder of 31 when 1186 is divided by these natural numbers? (UPSC 2023)

(a) 6

(b) 7

(c) 8

(d) 9

2. A 2 digit number is reversed. The larger of the two numbers is divided by the smaller one. What is the largest possible remainder?

(a) 9

(b) 27

(c) 36

(d) 45

3. What is the remainder when 32X23+45X54+67X76 is divided by 7?

(a) 3

(b) 4

(c) 5

(d) 6

4. If 48+50+78+104+14A is divided by 7, remainder is 5, where A is a digit. Then what is the value for A?

(a) 2

(b) 3

(c) 4

(d) 5

5. 98∧100+ 100∧100 is divided by 9, then remainder is

(a) 7

(b) 0

(c) 2

(d) 9

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